3(x^2)+((3)(1x)/2)=0

Solution for 3(x^2)+((3)(1x)/2)=0 equation:

3(x^2)+((3)(1x)/2)=0

We add all the numbers together, and all the variables

3x^2+(+31x/2)=0

We get rid of parentheses

3x^2+31x/2=0

We multiply all the terms by the denominator


3x^2*2+31x=0

Wy multiply elements

6x^2+31x=0

a = 6; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·6·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*6}=\frac{-62}{12}
=-5+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*6}=\frac{0}{12}
=0
$